[Konstantin-78]

Вот тут еще вариант:

Код:

SELECT Q.proposal_id
  FROM (
    SELECT proposal_id, sort_work_id
      FROM Devices
      GROUP BY proposal_id, sort_work_id) Q
  GROUP BY Q.proposal_id
  HAVING Count(*)=2 AND SUM(CASE WHEN Q.sort_work_id IN (1,2) 1 ELSE 0 END)=2   //строгое

  HAVING Count(*)>=2 AND SUM(CASE WHEN Q.sort_work_id IN (1,2) 1 ELSE 0 END)=2  //не строгое