[kukushonka]

Нус-с-с домучали со знакомым програмку, теперь следующая проблема, может кто знает, как во время движения сделать масштабирование(уменьшение) с коэффициентом кх=ку=1

вот код:

Код:

unit Unit1;

interface

uses
  Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
  Dialogs, StdCtrls, ExtCtrls;

type
  TForm1 = class(TForm)
    Button1: TButton;
    Button2: TButton;
    Button3: TButton;
    Timer1: TTimer;
    procedure Button2Click(Sender: TObject);
    procedure Timer1Timer(Sender: TObject);
    procedure Button1Click(Sender: TObject);
    procedure Button3Click(Sender: TObject);
  private
    { Private declarations }
  public
    { Public declarations }
  end;

var
  Form1: TForm1;

implementation

{$R *.dfm}
var xc,yc,x1,x2,x3,y1,y2,y3,x4,y4,f,xc1,yc1:real;     i,fi,dfi:integer;
const r=200;   

procedure risunok;
begin
form1.canvas.moveto(100,260);
form1.canvas.lineto(60,300);
form1.canvas.lineto(100,340);
form1.canvas.lineto(140,300);
form1.canvas.lineto(100,260);
end;
procedure TForm1.Button1Click(Sender: TObject);
begin
form1.canvas.rectangle(0,0,clientwidth,clientheight-100);
risunok;
end;
procedure TForm1.Button2Click(Sender: TObject);
begin
    timer1.enabled:=true;
    xc1:=350;   fi:=0;   dfi:= 1;
    yc1:=200;
end;

procedure TForm1.Button3Click(Sender: TObject);
begin
close;
end;

procedure TForm1.Timer1Timer(Sender: TObject);
begin
  form1.Canvas.Rectangle(0,0,clientwidth,clientheight-100);
  fi:=fi+dfi;
  xc:=xc1+round(50*cos(fi*pi/180));
  yc:=yc1-round(50*sin(fi*pi/180));
  x1:=xc;
  x2:=xc-40;
  x3:=xc;
  x4:=xc+40;
  y1:=yc-40;
  y2:=yc;
  y3:=yc+40;
  y4:=yc;
  form1.canvas.moveto(round(x1),round(y1));
  form1.canvas.lineto(round(x2),round(y2));
  form1.canvas.lineto(round(x3),round(y3));
  form1.canvas.lineto(round(x4),round(y4));
  form1.canvas.lineto(round(x1),round(y1));   
end;
 


end.