1 способ:
Код:
Image2.Picture.Assign(Image1.Picture);
2 способ:
Код:
var
MemoryStream: TMemoryStream;
begin
MemoryStream:=TMemoryStream.Create;
try
Image1.Picture.Bitmap.SaveToStream(MemoryStream);
MemoryStream.Position:=0;
Image2.Picture.Bitmap.LoadFromStream(MemoryStream);
finally
MemoryStream.Free;
end;
end;
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Пишу программы за еду.
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